If the radius of a circle be reduced by 50% its area is reduced by:_________?
		A. 25 %
B. 50%
C. 75%
D. 100%
		A. 25 %
B. 50%
C. 75%
D. 100%
		A. Rs. 400
B. Rs. 450
C. Rs. 460
D. Rs. 480
Explanation:
Let the sum be Rs. P. Then,
[P(1 + 25/(2 * 100))2 – P] = 510
P[(9/8)2 – 1] = 510.
Sum = Rs. 1920
So, S.I. = (1920 * 25 * 2) / (2 * 100) = Rs. 480
		A. 10
B. 20
C. 40
D. 73
Explanation:
Let there be x pupils in the class.
Total increase in marks = (x * 1/2) = x/2
x/2 = (83 – 63) => x/2 = 20 => x = 40
		A. Rs.325
B. Rs.545
C. Rs.560
D. Rs.550
		A. 4000
B. 4400
C. 5000
D. 5400
		A. 7/8
B. 13/16
C. 31/40
D. 63/80
Explanation:
L.C.M of 8, 16, 40 and 80 = 80.
7/8 = 70/80; 13/16 = 65/80; 31/40 = 62/80
Since, 70/80 > 63/80 > 65/80 > 62/80,
So, 7/8 > 63/80 > 13/16 > 31/40
So, 7/8 is the largest.
		A. 12:00 pm
B. 2:00 am
C. 12:00 am
D. 10:00 pm
Jameel works for 5 hours. So he completes 5/15 = 1/3 of the task Nasir has to complete 2/3rd of the task 12*2/3 = 8 hours are needed. He completes the task at 12:00 am.