Find the value of x when y = 5, if x varies directly as 4y-1 and x = 14 when y = 2.

A. 38
B. 35
C. 10
D. 28
Let z = 4y-1
When x = 14, y = 2, z = (4*2) – 1 = 7
Now, x varies directly as z = 4y-1
When y = 5, z = (4*5) – 1 = 19
x 14 7
y – 19
Therefore, x = (14*19)/7 = 38