A. 16%
B. 16 1/3 %
C. 20%
D. 16 3/5 %
X=100 y=125
125——–25
100——–? => 20%
A. 60 gallons
B. 100 gallons
C. 120 gallons
D. 180 gallons
Explanation:
Work done by the waste pipe in 1 minute = 1/15 – (1/20 + 1/24) = – 1/40
Volume of 1/40 part = 3 gallons
Volume of whole = 3 * 40 = 120 gallons.
A. 12:00 pm
B. 2:00 am
C. 12:00 am
D. 10:00 pm
Jameel works for 5 hours. So he completes 5/15 = 1/3 of the task Nasir has to complete 2/3rd of the task 12*2/3 = 8 hours are needed. He completes the task at 12:00 am.
A. 30m
B. 40m
C. 50m
D. 60m
Explanation:
Each side of the square = 160/4m =40 cm
2(l+b) = 160
=> (l+b) = 80 (40) 2 –lb = 100
=> lb =(1600 – 100) = 1500 (l-b) 2 = (l+b) 2 – 4lb
= (80) 2 -4 x 1500 =(6400 -6000) = 400 (l-b) = 20
Therefore, l+b = 80, l-b =20
=> 2l =100
=> l= 50m
A. 16 toffees
B. 20 toffees
C. 25 toffees
D. 24 toffees
Explanation:
He sells 20 toffees
S.P = Rs. 1 and loss = 4%
C.P = (11/96 × 1) = Rs. 25/24
Gain = 20%
S.P = Rs. (120/100 × 25/24) = Rs. 5/4
Rs. 5/4 toffees sold = 20
Rs. 1 toffees sold = (20 × 4/5) = 16
A. 72
B. 72.9
C. 73.8
D. 74.7
E. None of these
Explanation:
Let the initial quantity of milk in vessel be T litres.
Let us say y litres of the mixture is taken out and replaced by water for n times, alternatively.
Quantity of milk finally in the vessel is then given by [(T – y)/T]n * T
For the given problem, T = 90, y = 9 and n = 2.
Hence, quantity of milk finally in the vessel
= [(90 – 9)/90]2 (90) = 72.9 litres.
A. 40
B. 50
C. 60
D. 70
E. None of these
Explanation:
Let the number be
2 + 1/2[1/3(a/5)] = a/15
=> 2 = a/30 => a = 60