If dice (I), (II) and (III) have even number of dots on their bottom faces and the dice (IV), (V) and (VI) have odd number of dots on their top faces, then what would be the difference in the total number of top faces between there two sets?

Question: If dice (I), (II) and (III) have even number of dots on their bottom faces and the dice (IV), (V) and (VI) have odd number of dots on their top faces, then what would be the difference in the total number of top faces between there two sets?
[A].

0

[B].

2

[C].

4

[D].

6

Answer: Option D

Explanation:

No. of faces on the top faces of the dice (I), (II) and (III) are 5, 1 and 5 respectively.

Therefore, Total of these numbers = 5 + 1 + 5 = 11

No. of dots on the top faces of the dice (IV), (V) and (VI) are 1, 3 and 1 respectively.

Therefore, Total of these numbers = 1 + 3 + 1 = 5

Required difference = 11 – 5 = 6