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A current 10 sin (200t) A flows through a 5 mH inductance. The expression for voltage is

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Question: A current 10 sin (200t) A flows through a 5 mH inductance. The expression for voltage is
[A].

10 sin (200t + 90°)

[B].

10 sin (200t – 90°)

[C].

10 sin(1000t + 90°)

[D].

10 sin (1000t – 90°)

Answer: Option D

Explanation:

Z = jXL = jωL = = 1∠90° and V = IXL