A is three times as old as B. C was twice-as old as A four years ago. In four years’ time, A will be 31. What are the present ages of B and C ?

Question: A is three times as old as B. C was twice-as old as A four years ago. In four years’ time, A will be 31. What are the present ages of B and C ?
[A].

9, 46

[B].

9, 50

[C].

10, 46

[D].

10, 50

Answer: Option B

Explanation:

We have : A = 3B …(i) and

C – 4 = 2 (A – 4) …(ii)

Also, A + 4 = 31 or A= 31-4 = 27.

Putting A = 27 in (i), we get: B = 9.

Putting A = 27 in (ii), we get C = 50.