Question:
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
[A].
In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
[A].
| 1 |
| 3 |
[B].
| 3 |
| 4 |
[C].
| 7 |
| 19 |
[D].
| 8 |
| 21 |
Answer: Option A
Explanation:
Total number of balls = (8 + 7 + 6) = 21.
| Let E | = event that the ball drawn is neither red nor green |
| = event that the ball drawn is blue. |
n(E) = 7.
| P(E) = | n(E) | = | 7 | = | 1 | . |
| n(S) | 21 | 3 |