On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:

Question: On dividing 2272 as well as 875 by 3-digit number N, we get the same remainder. The sum of the digits of N is:
[A].

10

[B].

11

[C].

12

[D].

13

Answer: Option A

Explanation:

Clearly, (2272 – 875) = 1397, is exactly divisible by N.

Now, 1397 = 11 x 127

The required 3-digit number is 127, the sum of whose digits is 10.