If 2994 ÷ 14.5 = 172, then 29.94 ÷ 1.45 = ?
[A].
[B].
[C].
[D].
Answer: Option C
Explanation:
| 29.94 | = | 299.4 |
| 1.45 | 14.5 |
| = | 2994 | x | 1 | [ Here, Substitute 172 in the place of 2994/14.5 ] | ||
| 14.5 | 10 |
| = | 172 |
| 10 |
= 17.2
[B].
[C].
[D].
Answer: Option C
Explanation:
| 29.94 | = | 299.4 |
| 1.45 | 14.5 |
| = | 2994 | x | 1 | [ Here, Substitute 172 in the place of 2994/14.5 ] | ||
| 14.5 | 10 |
| = | 172 |
| 10 |
= 17.2
[B].
[C].
[D].
Answer: Option C
Explanation:
Let the numbers be x and x + 2.
Then, (x + 2)2 – x2 = 84
4x + 4 = 84
4x = 80
x = 20.
The required sum = x + (x + 2) = 2x + 2 = 42.
[B].
[C].
[D].
Answer: Option D
Explanation:
| For an income of Re. 1 in 9% stock at 96, investment = Rs. | 96 | = Rs. | 32 | ||
| 9 | 3 |
| For an income Re. 1 in 12% stock at 120, investment = Rs. | 120 | = Rs. 10. | ||
| 12 |
| Ratio of investments = | 32 | : 10 = 32 : 30 = 16 : 15. |
| 3 |
[B].
[C].
[D].
Answer: Option B
Explanation:
| (.000216)1/3 | = | 216 | 1/3 | ||
| 106 |
| = | 6 x 6 x 6 | 1/3 | ||
| 102 x 102 x 102 |
| = | 6 |
| 102 |
| = | 6 |
| 100 |
= 0.06
[B].
[C].
[D].
Answer: Option D
Explanation:
Let the number of hens be x and the number of cows be y.
Then, x + y = 48 …. (i)
and 2x + 4y = 140 x + 2y = 70 …. (ii)
Solving (i) and (ii) we get: x = 26, y = 22.
The required answer = 26.
[B].
[C].
[D].
Answer: Option A
Explanation:
19657 Let x – 53651 = 9999
33994 Then, x = 9999 + 53651 = 63650
—–
53651
—–
[B].
[C].
[D].
Answer: Option B
Explanation:
Suppose they meet x hours after 7 a.m.
Distance covered by A in x hours = 20x km.
Distance covered by B in (x – 1) hours = 25(x – 1) km.
20x + 25(x – 1) = 110
45x = 135
x = 3.
So, they meet at 10 a.m.