[B].
[C].
[D].
Answer: Option D
Explanation:
| 1 ÷ 0.2 = | 1 | = | 10 | = 5; |
| 0.2 | 2 |
0.2 = 0.222…;
(0.2)2 = 0.04.
0.04 < 0.2 < 0.22….<5.
Since 0.04 is the least, so (0.2)2 is the least.
[B].
[C].
[D].
Answer: Option B
Explanation:
Required number = H.C.F. of (1657 – 6) and (2037 – 5)
= H.C.F. of 1651 and 2032 = 127.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
| 27x + 17y | = 23 | |
| x+ y |
27x + 17y = 23x + 23y
4x = 6y
| x | = | 3 | . | |
| y | 2 |
[B].
[C].
| 20 | 3 | days |
| 17 |
[D].
Answer: Option B
Explanation:
Ratio of times taken by A and B = 100 : 130 = 10 : 13.
Suppose B takes x days to do the work.
| Then, 10 : 13 :: 23 : x x = | 23 x 13 | x = | 299 | . | ||
| 10 | 10 |
| A’s 1 day’s work = | 1 | ; |
| 23 |
| B’s 1 day’s work = | 10 | . |
| 299 |
| (A + B)’s 1 day’s work = | 1 | + | 10 | = | 23 | = | 1 | . | ||
| 23 | 299 | 299 | 13 |
Therefore, A and B together can complete the work in 13 days.
[B].
[C].
[D].
Answer: Option A
Explanation:
Ratio of rates of working of A and B = 2 : 1.
So, ratio of times taken = 1 : 2.
| B’s 1 day’s work = | 1 | . |
| 12 |
| A’s 1 day’s work = | 1 | ; (2 times of B’s work) |
| 6 |
| (A + B)’s 1 day’s work = | 1 | + | 1 | = | 3 | = | 1 | . | ||
| 6 | 12 | 12 | 4 |
So, A and B together can finish the work in 4 days.
[B].
[C].
[D].
Answer: Option B
Explanation:
To obtain Rs. 10, investment = Rs. 96.
| To obtain Rs. 650, investment = Rs. | 96 | x 650 | = Rs. 6240. | ||
| 10 |
[B].
[C].
[D].
Answer: Option B
Explanation:
Go on multiplying with 1, 2, 3, 4, 5, 6 to get next number.
So, 96 is wrong.