The rational number for recurring decimal 0.125125…. is:
The rational number for recurring decimal 0.125125…. is:
[A].
| 63 |
| 487 |
[B].
| 119 |
| 993 |
[C].
| 125 |
| 999 |
[D].
Answer: Option C
Explanation:
| 0.125125… = 0.125 = | 125 |
| 999 |
| 63 |
| 487 |
[B].
| 119 |
| 993 |
[C].
| 125 |
| 999 |
[D].
Answer: Option C
Explanation:
| 0.125125… = 0.125 = | 125 |
| 999 |
A. 6.24 km
B. 6 km
C. 5.76 km
D. 5.66 km
Explanation:
M = 6
S = 1.2
DS = 7.2
US = 4.8
x/7.2 + x/4.8 = 1
x = 2.88
D = 2.88 * 2 = 5.76
A. 40 minutes
B. 1 hour
C. 1 hr 15 min
D. 1 hr 30 min
[B].
[C].
[D].
Answer: Option A
Explanation:
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
| Then, | 5x + 3 | = | 11 |
| 4x + 3 | 9 |
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x – 44x = 33 – 27
x = 6.
Anand’s present age = 4x = 24 years.
A. Rs.600
B. Rs.500
C. Rs.400
D. Rs.300
Explanation:
Sum be Rs.100
S.I = Rs.(1000/100) =Rs.10
C.I = Rs.[{100 × (1 +5/100) 2} – 100] =Rs.41/4
Difference C.I amd S. I = Rs.(41/4 – 10) =Rs.25
25 : 1.50 : : 100 : x
Therefore x = ((1.50 ×100)/25) = Rs.600
[B].
[C].
[D].
Answer: Option B
Explanation:
Let their present ages be 4x, 7x and 9x years respectively.
Then, (4x – 8) + (7x – 8) + (9x – 8) = 56
20x = 80
x = 4.
Their present ages are 4x = 16 years, 7x = 28 years and 9x = 36 years respectively.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352.
Since the number increases on reversing the digits, so the hundred’s digits is smaller than the unit’s digit.
Hence, required number = 253.