Question: A cistern 6m long and 4 m wide contains water up to a depth of 1 m 25 cm. The total area of the wet surface is:
[A].49 m2
50 m2
53.5 m2
55 m2
[A].
[B].
[C].
[D].
Answer: Option A
Explanation:
Area of the wet surface | = [2(lb + bh + lh) – lb] |
= 2(bh + lh) + lb | |
= [2 (4 x 1.25 + 6 x 1.25) + 6 x 4] m2 | |
= 49 m2. |