Question:
A fires 5 shots to B’s 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
[A].30 birds
60 birds
72 birds
90 birds
A fires 5 shots to B’s 3 but A kills only once in 3 shots while B kills once in 2 shots. When B has missed 27 times, A has killed:
[A].
[B].
[C].
[D].
Answer: Option A
Explanation:
Let the total number of shots be x. Then,
| Shots fired by A = | 5 | x |
| 8 |
| Shots fired by B = | 3 | x |
| 8 |
| Killing shots by A = | 1 | of | 5 | x | = | 5 | x |
| 3 | 8 | 24 |
| Shots missed by B = | 1 | of | 3 | x | = | 3 | x |
| 2 | 8 | 16 |
| 3x | = 27 or x = | 27 x 16 | = 144. | |||
| 16 | 3 |
| Birds killed by A = | 5x | = | 5 | x 144 | = 30. | ||
| 24 | 24 |