A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?

Byadmin July 18, 2022

Question:
A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?

[A].

230 m

[B].

240 m

[C].

260 m

[D].

270 m

Answer: Option D

Explanation:

Speed =		72 x	5	m/sec	= 20 m/sec.
			18

Time = 26 sec.

Let the length of the train be x metres.

Then,	x + 250	= 20
	26

x + 250 = 520

x = 270.

Aptitude | Odd Man Out And Series

7, 26, 63, 124, 215, 342, (….)

Question:
7, 26, 63, 124, 215, 342, (….)

[A].

481
[B].
511
[C].
391
[D].
421

Answer: Option B

Explanation:

Numbers are (23 – 1), (33 – 1), (43 – 1), (53 – 1), (63 – 1), (73 – 1) etc.

So, the next number is (83 – 1) = (512 – 1) = 511.

Read More 7, 26, 63, 124, 215, 342, (….)
Aptitude | Banker's Discount

The banker’s discount on a bill due 4 months hence at 15% is Rs. 420. The true discount is:

Question:
The banker’s discount on a bill due 4 months hence at 15% is Rs. 420. The true discount is:

[A].

Rs. 400
[B].
Rs. 360
[C].
Rs. 480
[D].
Rs. 320

Answer: Option A

Explanation:

T.D.

= B.D. x 100

100 + (R x T)

= Rs. 420 x 100

100 + 15 x 1

3

= Rs. 420 x 100

105

= Rs. 400.

Read More The banker’s discount on a bill due 4 months hence at 15% is Rs. 420. The true discount is:
Compound Interest | Mathematics Mcqs

What is the difference between the compound interest on Rs.12000 at 20% p.a. for one year when compounded yearly and half yearly?

What is the difference between the compound interest on Rs.12000 at 20% p.a. for one year when compounded yearly and half yearly?

A. Rs.140
B. Rs.120
C. Rs.130
D. Rs.110
E. None of these.

Read More What is the difference between the compound interest on Rs.12000 at 20% p.a. for one year when compounded yearly and half yearly?
Compound Interest | Mathematics Mcqs

A money lender borrows money at 4% P.a and pays interest at the end of the year. He lends it at 6% P.a compound interest compounded half-yearly and receives the interest at the end of the year. Thus be gains Rs 104.50 a year. The amount of money he borrows is_________?

A money lender borrows money at 4% P.a and pays interest at the end of the year. He lends it at 6% P.a compound interest compounded half-yearly and receives the interest at the end of the year. Thus be gains Rs 104.50 a year. The amount of money he borrows is_________?

A. Rs 4500
B. Rs 5000
C. Rs 5500
D. Rs 6000
Explanation:
Let the money borrowed be Rs x
Interest paid by the money lender = Rs (x × 4/100 × 1) =Rs x/25
Interest received by the money lender
= Rs [x × (1 + 3/100)2 – x]
= Rs(x × 103/100 × 103/100 – x)
Gain = Rs (609x/1000 – x /25)
= Rs 209x/1000 = Rs 609x/10000
Therefore 209x/10000 = 104.50
=> 209x = 1045000
=> x = 5000
Hence money borrowed = Rs 5000

Read More A money lender borrows money at 4% P.a and pays interest at the end of the year. He lends it at 6% P.a compound interest compounded half-yearly and receives the interest at the end of the year. Thus be gains Rs 104.50 a year. The amount of money he borrows is_________?
Aptitude | Problems on Numbers

In a two-digit, if it is known that its unit’s digit exceeds its ten’s digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is:

Question:
In a two-digit, if it is known that its unit’s digit exceeds its ten’s digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is:

[A].

24
[B].
26
[C].
42
[D].
46

Answer: Option A

Explanation:

Let the ten’s digit be x.

Then, unit’s digit = x + 2.

Number = 10x + (x + 2) = 11x + 2.

Sum of digits = x + (x + 2) = 2x + 2.

(11x + 2)(2x + 2) = 144

22×2 + 26x – 140 = 0

11×2 + 13x – 70 = 0

(x – 2)(11x + 35) = 0

x = 2.

Hence, required number = 11x + 2 = 24.

Read More In a two-digit, if it is known that its unit’s digit exceeds its ten’s digit by 2 and that the product of the given number and the sum of its digits is equal to 144, then the number is:
Aptitude | Time And Distance

If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

Question:
If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

[A].

50 km
[B].
56 km
[C].
70 km
[D].
80 km

Answer: Option A

Explanation:

Let the actual distance travelled be x km.

Then, x = x + 20

10 14

14x = 10x + 200

4x = 200

x = 50 km.

Read More If a person walks at 14 km/hr instead of 10 km/hr, he would have walked 20 km more. The actual distance travelled by him is:

Similar Posts