[B].
[C].
[D].
Answer: Option B
Explanation:
Go on adding 7, 9, 11, 13, 15, 17 respectively to obtain the next number.
So, 33 is wrong. It must be 35
A. Rs.4400
B. Rs.4445
C. Rs.4460
D. Rs.4520
Explanation:
Sum be P
P(1 + R/100)3 = 6690 – (i)
P(1 + R/100)2 = 10, 035 – (ii)
By dividing (i) and (ii)
(1 + R/100)3 = 10035/6690 = 3/2
Therefore, P = (6690 x 2/3) = Rs. 4460
A. Rs 50
B. Rs 60
C. Rs 61
D. Rs 600
Explanation:
S.I = Rs(8000 × 5/100 ×3) = Rs 1200
C.I = Rs [8000 × (1+5/100)3– 8000
= Rs [(8000 × 21/20×21/20×21/20)-8000]
=Rs (9261-8000)=Rs 1261
(c.I)-(S.I) = Rs (1261 – 1200) = Rs61.
[B].
[C].
[D].
Answer: Option B
Explanation:
Sum of the present ages of husband, wife and child = (27 x 3 + 3 x 3) years = 90 years.
Sum of the present ages of wife and child = (20 x 2 + 5 x 2) years = 50 years.
Husband’s present age = (90 – 50) years = 40 years.
[B].
[C].
[D].
Answer: Option B
Explanation:
Sum of decimal places = 7.
Since the last digit to the extreme right will be zero (since 5 x 4 = 20), so there will be 6 significant digits to the right of the decimal point.
[B].
[C].
[D].
Answer: Option D
Explanation:
We shall find the day on 1st April, 2001.
1st April, 2001 = (2000 years + Period from 1.1.2001 to 1.4.2001)
Odd days in 1600 years = 0
Odd days in 400 years = 0
Jan. Feb. March April
(31 + 28 + 31 + 1) = 91 days 0 odd days.
Total number of odd days = (0 + 0 + 0) = 0
On 1st April, 2001 it was Sunday.
In April, 2001 Wednesday falls on 4th, 11th, 18th and 25th.
[B].
[C].
[D].
Answer: Option D
Explanation:
| Amount of milk left after 3 operations = | 40 | 1 – | 4 | 3 | litres | |||
| 40 |
| = | 40 x | 9 | x | 9 | x | 9 | = 29.16 litres. | ||
| 10 | 10 | 10 |