The average molecular weight of a flue gas having the composition by volume as CO2 = 25%, O2 = 25%, N2 = 50% will be___________________?
A. 27.6
B. 23
C. 47.3
D. 42.9
A. 27.6
B. 23
C. 47.3
D. 42.9
A. C + H2O ↔ CO + H2
B. C + 2H2O ↔ CO2 + 2H2
C. CO + H2O ↔ CO2 + H2
D. None of these
A. Calorific value, cleanliness and relatively low distribution cost (due to its low specific gravity)
B. Adiabatic flame temperature
C. Heat release rate (thus requiring smaller combustion chamber)
D. All A., B. and C.
A. 8
B. 12
C. 22
D. 36
[B].
[C].
[D].
Answer: Option C
Explanation:
No answer description available for this question.
A. Increase the adiabatic flame temperature
B. Increase the calorific value of the fuel
C. Complete the combustion of fuel
D. Reduce its requirement for effecting the complete combustion
[B].
[C].
[D].
Answer: Option C
Explanation:
No answer description available for this question.