[B].
[C].
[D].
Answer: Option B
Explanation:
Le the required time be x seconds.
More metres, More time (Direct Proportion)
0.128 : 25 :: 1 : x 0.128x = 25 x 1
| x = | 25 | = | 25 x 1000 |
| 0.128 | 128 |
x = 195.31.
Required time = 195 sec (approximately).
[B].
[C].
[D].
Answer: Option B
Explanation:
| Work done by X in 4 days = | 1 | x 4 | = | 1 | . | ||
| 20 | 5 |
| Remaining work = | 1 – | 1 | = | 4 | . | ||
| 5 | 5 |
| (X + Y)’s 1 day’s work = | 1 | + | 1 | = | 8 | = | 2 | . | ||
| 20 | 12 | 60 | 15 |
| Now, | 2 | work is done by X and Y in 1 day. |
| 15 |
| So, | 4 | work will be done by X and Y in | 15 | x | 4 | = 6 days. | ||
| 5 | 2 | 5 |
Hence, total time taken = (6 + 4) days = 10 days.
[B].
[C].
[D].
Answer: Option A
Explanation:
Length of largest tile = H.C.F. of 1517 cm and 902 cm = 41 cm.
Area of each tile = (41 x 41) cm2.
| Required number of tiles = | 1517 x 902 | = 814. | ||
| 41 x 41 |
[B].
[C].
[D].
Answer: Option B
Explanation:
| Speed = | 300 | m/sec = | 50 | m/sec. | ||
| 18 | 3 |
Let the length of the platform be x metres.
| Then, | x + 300 | = | 50 | ||
| 39 | 3 |
3(x + 300) = 1950
x = 350 m.
A. 6.06%
B. 6.07%
C. 6.08%
D. 6.09%
Explanation:
Amount of Rs. 100 for 1 year when compounded half-yearly = [100 * (1 + 3/100)2] = Rs. 106.09 Effective rate = (106.09 – 100) = 6.09%
[B].
[C].
[D].
Answer: Option B
Explanation:
Required numbers are 102, 108, 114, … , 996
This is an A.P. in which a = 102, d = 6 and l = 996
Let the number of terms be n. Then,
a + (n – 1)d = 996
102 + (n – 1) x 6 = 996
6 x (n – 1) = 894
(n – 1) = 149
n = 150.