[B].
[C].
[D].
Answer: Option A
Explanation:
In each number except 751, the difference of third and first digit is the middle one.
[B].
[C].
[D].
Answer: Option D
Explanation:
| Amount of Rs. 100 for 1 year when compounded half-yearly |
= Rs. | 100 x | 1 + | 3 | 2 | = Rs. 106.09 | |||||
| 100 |
Effective rate = (106.09 – 100)% = 6.09%
[B].
[C].
[D].
Answer: Option B
Explanation:
| 8796 x 223 + 8796 x 77 | = 8796 x (223 + 77) [Ref: By Distributive Law ] |
| = (8796 x 300) | |
| = 2638800 |
A. 6.06%
B. 6.07%
C. 6.08%
D. 6.09%
Explanation:
Amount of Rs. 100 for 1 year when compounded half-yearly = [100 * (1 + 3/100)2] = Rs. 106.09 Effective rate = (106.09 – 100) = 6.09%
[B].
[C].
[D].
Answer: Option B
Explanation:
| 2 kmph = | 2 x | 5 | m/sec = | 5 | m/sec. | ||
| 18 | 9 |
| 4 kmph = | 4 x | 5 | m/sec = | 10 | m/sec. | ||
| 18 | 9 |
Let the length of the train be x metres and its speed by y m/sec.
| Then, | x | = 9 and | x | = 10. | ||||
|
|
9y – 5 = x and 10(9y – 10) = 9x
9y – x = 5 and 90y – 9x = 100.
On solving, we get: x = 50.
Length of the train is 50 m.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let rate = R% and time = R years.
| Then, | 1200 x R x R | = 432 | ||
| 100 |
12R2 = 432
R2 = 36
R = 6.
Video Explanation: https://youtu.be/TjjI4iRkzT0
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352.
Since the number increases on reversing the digits, so the hundred’s digits is smaller than the unit’s digit.
Hence, required number = 253.