[B].
[C].
[D].
Answer: Option B
Explanation:
There are two series (8, 11, 14, 17, 20) and (7, 12, 17, 22) increasing by 3 and 5 respectively.
[B].
[C].
[D].
Answer: Option C
Explanation:
Given expression = (11.98)2 + (0.02)2 + 11.98 x x.
For the given expression to be a perfect square, we must have
11.98 x x = 2 x 11.98 x 0.02 or x = 0.04
[B].
[C].
[D].
Answer: Option D
Explanation:
| Principal |
|
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|
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| = Rs. 8925. |
[B].
[C].
[D].
Answer: Option B
Explanation:
x = 13p + 11 and x = 17q + 9
13p + 11 = 17q + 9
17q – 13p = 2
| q = | 2 + 13p |
| 17 |
| The least value of p for which q = | 2 + 13p | is a whole number is p = 26 |
| 17 |
x = (13 x 26 + 11)
= (338 + 11)
= 349
[B].
[C].
[D].
Answer: Option C
Explanation:
Clearly, the numbers which have 1 or 9 in the unit’s digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
| Required percentage = | 14 | x 100 | % = 20%. | |
| 70 |
Video Explanation: https://youtu.be/cBamI6iRNIA
[B].
[C].
[D].
Answer: Option C
Explanation:
Given numbers are 1.08, 0.36 and 0.90. H.C.F. of 108, 36 and 90 is 18,
H.C.F. of given numbers = 0.18.
A. 5 %
B. 10 %
C. 15 %
D. 20 %
Explanation:
P be the principle and R % Per annum be the rate.
P(1 + R/100) 3 = 10648 – (i)
P(1 + R/100) 2 = 9680 – (ii)
By dividing (i) and (ii)
(1 +R/100) = 10648/9680 Or
R/100 = 968/9680 = 1/10 or
R = 10 %