8, 24, 12, 36, 18, 54, (….)
Question: 8, 24, 12, 36, 18, 54, (….)
[A].
27
108
68
72
[A].
[B].
[C].
[D].
Answer: Option A
Explanation:
Numbers are alternatively multiplied by 3 and divided by 2.
So, the next number = 54 ÷ 2 = 27.
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A man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat (in still water) and the stream is:
Question:
A man takes twice as long to row a distance against the stream as to row the same distance in favour of the stream. The ratio of the speed of the boat (in still water) and the stream is:
[A].2 : 1 [B].
3 : 1 [C].
3 : 2 [D].
4 : 3 Answer: Option B
Explanation:
Let man’s rate upstream be x kmph.
Then, his rate downstream = 2x kmph.
(Speed in still water) : (Speed of stream) = 2x + x : 2x – x 2 2 = 3x : x 2 2 = 3 : 1.
A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?
Question:
A watch which gains uniformly is 2 minutes low at noon on Monday and is 4 min. 48 sec fast at 2 p.m. on the following Monday. When was it correct?
[A].2 p.m. on Tuesday [B].
2 p.m. on Wednesday [C].
3 p.m. on Thursday [D].
1 p.m. on Friday Answer: Option B
Explanation:
Time from 12 p.m. on Monday to 2 p.m. on the following Monday = 7 days 2 hours = 170 hours.
The watch gains 2 + 4 4 min. or 34 min. in 170 hrs. 5 5 Now, 34 min. are gained in 170 hrs. 5 2 min. are gained in 170 x 5 x 2 hrs = 50 hrs. 34 Watch is correct 2 days 2 hrs. after 12 p.m. on Monday i.e., it will be correct at 2 p.m. on Wednesday.
If 20% of a = b, then b% of 20 is the same as:
Question:
If 20% of a = b, then b% of 20 is the same as:
[A].4% of a [B].
5% of a [C].
20% of a [D].
None of these Answer: Option A
Explanation:
20% of a = b 20 a = b. 100 b% of 20 = b x 20 = 20 a x 1 x 20 = 4 a = 4% of a. 100 100 100 100 A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will he take to go 5km in stationery water?
A boatman goes 2 km against the current of the stream in 1 hour and goes 1 km along the current in 10 minutes. How long will he take to go 5km in stationery water?A. 40 Minutes
B. 1 Hour
C. 1 hr 15 Min
D. 1 Hr 30 Min
Explanation:
Speed upstream = 2km/hr.
Speed downstream = 6 km/hr
Speed in stationary water = ½ (6 + 2) km/hr = 4 km/hr
Time is taken to cover 5 km in stationary water
= (1/4 x 5) 1 hr 15 minA man’s speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man’s speed against the current is:
Question:
A man’s speed with the current is 15 km/hr and the speed of the current is 2.5 km/hr. The man’s speed against the current is:
[A].8.5 km/hr [B].
9 km/hr [C].
10 km/hr [D].
12.5 km/hr Answer: Option C
Explanation:
Man’s rate in still water = (15 – 2.5) km/hr = 12.5 km/hr.
Man’s rate against the current = (12.5 – 2.5) km/hr = 10 km/hr.
Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years.
Find out the C.I on Rs.5000 at 4% p.a. compound half-yearly for 1 1/2 years.A. Rs.420.20
B. Rs.319.06
C. Rs.306.04
D. Rs.294.75
Explanation:
A = 5000(51/50)3
= 5306.04
5000
———–
306.04