72519 x 9999 = ?
[A].
[B].
[C].
[D].
Answer: Option A
Explanation:
| 72519 x 9999 | = 72519 x (10000 – 1) | 
| = 72519 x 10000 – 72519 x 1 | |
| = 725190000 – 72519 | |
| = 725117481. | 
[B].
[C].
[D].
Answer: Option D
Explanation:
Required numbers are 24, 30, 36, 42, …, 96
This is an A.P. in which a = 24, d = 6 and l = 96
Let the number of terms in it be n.
Then tn = 96 a + (n – 1)d = 96
24 + (n – 1) x 6 = 96
(n – 1) x 6 = 72
(n – 1) = 12
n = 13
Required number of numbers = 13.
		A. 6 kmph
B. 7 kmph
C. 8.5 kmph
D. 8 kmph
Explanation:
S = 1
M = x
DS = x + 1
US = x – 1
35/(x + 1) + 35/(x – 1) = 12
x = 6
[B].
[C].
[D].
Answer: Option B
Explanation:
l2 + b2 = 41.
Also, lb = 20.
(l + b)2 = (l2 + b2) + 2lb = 41 + 40 = 81
(l + b) = 9.
Perimeter = 2(l + b) = 18 cm.
[B].
[C].
[D].
Answer: Option D
Explanation:
Unit digit in (4137)754 = Unit digit in {[(4137)4]188 x (4137)2}
=Unit digit in { 292915317923361 x 17114769 }
= (1 x 9) = 9
		A. 3
B. 4
C. 4 (1/2)
D. Insufficient data
Explanation:
M = 4
S = 2
US =  4 – 2 = 2
D = 6
T = 6/2 = 3
[B].
[C].
[D].
Answer: Option D
Explanation:
| Speed = | 72 x | 5 | m/sec | = 20 m/sec. | |
| 18 | 
Time = 26 sec.
Let the length of the train be x metres.
| Then, | x + 250 | = 20 | 
| 26 | 
x + 250 = 520
x = 270.