7 2/5 of 110 / ? = 844
7 2/5 of 110 / ? = 844
A. 22
B. 24
C. 30
D. 28
Explanation:
? = 844 – 7 2/5 of 110 = 844 – 37 * 22 = 30
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A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?
A person crosses a 600 m long street in 5 minutes. What is his speed in km per hour?A. 8.2
B. 4.2
C. 6.1
D. 7.2The ratio of boys and girls in a class was 11:13. 8 girls and 4 boys join the class from this academic year and the ratio becomes 4:5. Find the strength of the class.
The ratio of boys and girls in a class was 11:13. 8 girls and 4 boys join the class from this academic year and the ratio becomes 4:5. Find the strength of the class.A. 96
B. 68
C. 72
D. 108
Let the number of boys and girls in the class be 11x and 13x. 4 boys and 8 girls join the class. Strength of the class
= 11x+13x+4+8
= 24x+12 (11x+4):(13x+8) = 4:5 5*(11x+4)=4*(13x+8) 55x+20=52x+32 3x=12 x=4 24x+12=108Which Muslim scientist wrote first book on Algebra ?
Which Muslim scientist wrote first book on Algebra ?A. Al-Khwarizmi
B. Ibn Sina
C. Archimedes
D. EuclidThe average age of a husband and a wife is 23 years when they were married five years ago but now the average age of the husband, wife and child is 20 years(the child was born during the interval). What is the present age of the child?
The average age of a husband and a wife is 23 years when they were married five years ago but now the average age of the husband, wife and child is 20 years(the child was born during the interval). What is the present age of the child?A. 1 year
B. 2 years
C. 3 years
D. 4 years
28 * 2 = 56
20 * 3 = 60
4 yearsFarjan and Kashif can complete a task in 30 days. Farjan leaves after 20 days and Kashif alone completes it in another 25 days. How many days does Farjan alone take to complete the entire task?
Farjan and Kashif can complete a task in 30 days. Farjan leaves after 20 days and Kashif alone completes it in another 25 days. How many days does Farjan alone take to complete the entire task?A. 50
B. 75
C. 60
D. 45
Part of work completed by Farjan and Kashif in a day
= 1/30 Part of work completed by them in 20 days
= 20/30 = 2/3 1/3 of the work is remaining. Kashif completes 1/3rd of the work in 25 days. Part of work completed by him in a day
= (1/3)÷25
= 1/75 (1/D)+(1/V) = 1/30 (1/D) = (1/30)-(1/75) = 1/50 Farjan can complete it in 50 days.Groups each containing 3 boys are to be formed out of 5 boys. A, B, C, D and E such that no group can contain both C and D together. What is the maximum number of such different groups?
Groups each containing 3 boys are to be formed out of 5 boys. A, B, C, D and E such that no group can contain both C and D together. What is the maximum number of such different groups?A. 5
B. 6
C. 7
D. 8
Explanation:
Maximum number of such different groups = ABC, ABD,ABE, BCE,BDE,CEA,DEA =7.
Alternate method:
Total number of way in which 3 boys can be selected out of 5 is 5C3
Number of ways in which CD comes together = 3 (CDA,CDB,CDE)
Therefore, Required number of ways = 5C3 -3
= 10-3 =7.