A. 1
B. 3/2
C. 2
D. 5/2
Explanation:
(64 + 9 + 9) / (2 * 20 + 1) = 82/41 = 2
A. 15 years
B. 17 years
C. 18 years
D. 19 years
Explanation:
Sum of the ages of 14 students
= (16 * 35) – (14 * 21) = 560 – 294 = 266
Required average = (266/14) = 19 years
A. 50
B. 47.5
C. 59
D. 52.5
Sum of the marks for the class of 30 students = 30 * 40 = 1200
Sum of the marks for the class of 50 students = 50 * 60 = 3000
Sum of the marks for the class of 80 students =
1200 + 3000 = 4200
Average marks of all the students = 4200/80 = 52.5
A. 7 years
B. 10 years
C. 15 years
D. 20 years
Explanation:
P(1 + R/100)5 = 2P => (1 + R/100)5 = 2
Let P(1 + R/100)n = 8P
=> (1 + R/100)n = 8 = 23 = {(1 + R/100)5}3
=> (1 + R/100)n = (1 + R/100)15 => n = 15 Required time = 15 years.
A. Rs. 400
B. Rs. 600
C. Cannot be determined
D. None of these
Explanation:
Profit is maximum when C.P is minimum and S.P Maximum.
Thus, C.P = Rs. (200 × 8) = Rs. 1600
S.P = Rs. (425 × 8) = Rs. 3400
Gain = Rs. 1800
A. 12
B. 15
C. 22
D. 20
Work done by P in 1 day = 1/15
Work done by Q in 1 day = 1/10
Work done by P and Q in 1 day = 1/15 + 1/10 = 1/6
Work done by P and Q in 2 days = 2 × (1/6) = 1/3
Remaining work = 1 – 1/3 = 2/3
Time taken by P to complete the remaining work 2/3 = (2/3) / (1/15) = 10 days
Total time taken = 2 + 10 = 12 days
A. 45 cm
B. 40 cm
C. 36 cm
D. 27 cm
Let the three sides be 4x,3x and 2x. 4x+3x+2x = 81 9x = 81 x = 9 Length of the largest side
= 4x = 36 cm