60 + 5 * 12 / (180/3) = _______?
		A. 60
B. 120
C. 13
D. 61
Explanation:
60 + 5 * 12 / (180/3) = 60 + 5 * 12 / (60)
= 60 + (5 * 12)/60 = 60 + 1 = 61.
		A. 60
B. 120
C. 13
D. 61
Explanation:
60 + 5 * 12 / (180/3) = 60 + 5 * 12 / (60)
= 60 + (5 * 12)/60 = 60 + 1 = 61.
Origin lies on the intersection of the x-axis and y-axis, i.e, (0,0).
		A. 16 toffees
B. 20 toffees
C. 25 toffees
D. 24 toffees
Explanation:
He sells 20 toffees
S.P = Rs. 1 and loss = 4%
C.P = (11/96 × 1) = Rs. 25/24
Gain = 20%
S.P = Rs. (120/100 × 25/24) = Rs. 5/4
Rs. 5/4 toffees sold = 20
Rs. 1 toffees sold = (20 × 4/5) = 16
		A. 55/601
B. 601/55
C. 11/120
D. 120/11
Explanation:
Let the numbers be a and b.
Then, a + b = 55 and ab = 5 * 120 = 600.
Required sum = 1/a + 1/b = (a + b)/ab = 55/600 = 11/120.
		A. 225 sq m
B. 220 sq m
C. 100 sq m
D. 30 sq m
		A. 49
B. 98
C. 492
D. 982
Explanation:
(492 * 324) / 324 = 492
		A. 1.44% loss
B. 14.4% profit
C. 14.4% loss
D. 0%
E. None of these
Explanation:
SP of each car is Rs. 325475, he gains 12% on first car and losses 12% on second car.
In this case, there will be loss and percentage of loss is given by = [(profit%)(loss%)]/100 = (12)(12)/100 % = 1.44%