[B].
[C].
[D].
Answer: Option A
Explanation:
Alternatively 23 is added and 17 is subtracted from the terms. So, 634 is wrong.
[B].
[C].
[D].
Answer: Option C
Explanation:
| Total time taken = | 160 | + | 160 | hrs. | = | 9 | hrs. | |
| 64 | 80 | 2 |
| Average speed = | 320 x | 2 | km/hr | = 71.11 km/hr. | |
| 9 |
[B].
[C].
[D].
Answer: Option C
Explanation:
| Part filled in 2 hours = | 2 | = | 1 |
| 6 | 3 |
| Remaining part = | 1 – | 1 | = | 2 | . | ||
| 3 | 3 |
| (A + B)’s 7 hour’s work = | 2 |
| 3 |
| (A + B)’s 1 hour’s work = | 2 |
| 21 |
C’s 1 hour’s work = { (A + B + C)’s 1 hour’s work } – { (A + B)’s 1 hour’s work }
| = | 1 | – | 2 | = | 1 | ||
| 6 | 21 | 14 |
C alone can fill the tank in 14 hours.
A. 40 Minutes
B. 1 Hour
C. 1 hr 15 Min
D. 1 Hr 30 Min
Explanation:
Speed upstream = 2km/hr.
Speed downstream = 6 km/hr
Speed in stationary water = ½ (6 + 2) km/hr = 4 km/hr
Time is taken to cover 5 km in stationary water
= (1/4 x 5) 1 hr 15 min
[B].
[C].
[D].
Answer: Option A
Explanation:
Let the average age of the whole team by x years.
11x – (26 + 29) = 9(x -1)
11x – 9x = 46
2x = 46
x = 23.
So, average age of the team is 23 years.
[B].
[C].
[D].
Answer: Option D
Explanation:
| (A + B)’s 20 day’s work = | 1 | x 20 | = | 2 | . | ||
| 30 | 3 |
| Remaining work = | 1 – | 2 | = | 1 | . | ||
| 3 | 3 |
| Now, | 1 | work is done by A in 20 days. |
| 3 |
Therefore, the whole work will be done by A in (20 x 3) = 60 days.
| 5 | 1 | % |
| 5 |
[B].
| 9 | 1 | % |
| 11 |
[C].
| 8 | 1 | % |
| 8 |
[D].
| 6 | 1 | % |
| 6 |
Answer: Option B
Explanation:
Let, B.D = Re. 1.
| Then, B.G. = Re. | 3 | . |
| 25 |
| T.D. = (B.D. – B.G.) = Re. | 1 – | 3 | = Re. | 22 | . | ||
| 25 | 25 |
| Sum = | 1 x (22/25) | = Rs. | 22 | . | ||
| 1-(22/25) | 3 |
| S.I. on Rs. | 22 | for 1 | 1 | years is Re. 1. |
| 3 | 2 |
| Rate = | 100 x 1 | % |
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