56, 72, 90, 110, 132, 150
[A].
[B].
[C].
[D].
Answer: Option D
Explanation:
The numbers are 7 x 8, 8 x 9, 9 x 10, 10 x 11, 11 x 12, 12 x 13.
So, 150 is wrong.
[B].
[C].
[D].
Answer: Option D
Explanation:
The numbers are 7 x 8, 8 x 9, 9 x 10, 10 x 11, 11 x 12, 12 x 13.
So, 150 is wrong.
[B].
[C].
[D].
Answer: Option A
Explanation:
(256)0.16 x (256)0.09 = (256)(0.16 + 0.09)
= (256)0.25
= (256)(25/100)
= (256)(1/4)
= (44)(1/4)
= 44(1/4)
= 41
= 4
[B].
[C].
[D].
Answer: Option C
Explanation:
Let the numbers be x and x + 2.
Then, (x + 2)2 – x2 = 84
4x + 4 = 84
4x = 80
x = 20.
The required sum = x + (x + 2) = 2x + 2 = 42.
[B].
[C].
[D].
Answer: Option D
Explanation:
Each of the numbers except 81 is a prime number.
[B].
[C].
[D].
Answer: Option A
Explanation:
Let x = 296q + 75
= (37 x 8q + 37 x 2) + 1
= 37 (8q + 2) + 1
Thus, when the number is divided by 37, the remainder is 1.
		A. Rs. 1550
B. Rs. 1650
C. Rs. 1750
D. Rs. 2000
[B].
[C].
[D].
Answer: Option D
Explanation:
Let the cost of a chair and that of a table be Rs. x and Rs. y respectively.
| Then, 10x = 4y or y = | 5 | x. | 
| 2 | 
15x + 2y = 4000
| 15x + 2 x | 5 | x = 4000 | 
| 2 | 
20x = 4000
x = 200.
| So, y = | 5 | x 200 | = 500. | ||
| 2 | 
Hence, the cost of 12 chairs and 3 tables = 12x + 3y
= Rs. (2400 + 1500)
= Rs. 3900.