[50 – {20 + 60% of (26/13 + 24/12 + 21) – 2} + 8] = 625/?
		A. 25
B. 125
C. 241/5
D. 253/5
Explanation:
[50 – {20 + 60% of (26/13 + 24/12 + 21) – 2} + 8] = 625/x => [50 – {20 + 3/5 of (25) – 2} + 8] = 625/x
=> [50 – 33 + 8] = 625/x  => x = 25
		A. 25
B. 125
C. 241/5
D. 253/5
Explanation:
[50 – {20 + 60% of (26/13 + 24/12 + 21) – 2} + 8] = 625/x => [50 – {20 + 3/5 of (25) – 2} + 8] = 625/x
=> [50 – 33 + 8] = 625/x  => x = 25
		A. 10
B. 8
C. 15
D. 7.50
Explanation:
Let the price of each note book be Rs.x.
Let the number of note books which can be brought for Rs.300 each at a price of Rs.x be y.
Hence xy = 300
=> y = 300/x
(x + 5)(y – 10) = 300 => xy + 5y – 10x – 50 = xy
=>5(300/x) – 10x – 50 = 0 => -150 + x2 + 5x = 0
multiplying both sides by -1/10x
=> x2 + 15x – 10x – 150 = 0
=> x(x + 15) – 10(x + 15) = 0
=> x = 10 or -15
As x>0, x = 10
		A. 9% loss
B. 400
C. 4000
D. 324
Explanation:
(30*30)/100 = 9%loss
		A. 256
B. 432
C. 512
D. 640
		A. 96
B. 68
C. 72
D. 108
Let the number of boys and girls in the class be 11x and 13x. 4 boys and 8 girls join the class. Strength of the class
= 11x+13x+4+8
= 24x+12 (11x+4):(13x+8) = 4:5 5*(11x+4)=4*(13x+8) 55x+20=52x+32 3x=12 x=4 24x+12=108
		A. 24
B. 23
C. 119
D. 120
Number of words which can be formed = 5! – 1 = 120 – 1 = 119.
		A. 49
B. 94
C. 83
D. Either (a) or (b)
E. None of these
Explanation:
Let the number be in the form of 10a + b
Number formed by interchanging a and b = 10b + a.
a + b = 13 — (1)
10b + a = 10a + b – 45
45 = 9a – 9b => a – b = 5 — (2)
Adding (1) and (2), we get
2a = 18 => a = 9 and b = 4
The number is: 94.