46080, 3840, 384, 48, 24, 2, 1
[A].
[B].
[C].
[D].
Answer: Option C
Explanation:
The terms are successively divided by 12, 10, 8, 6, …etc.
So, 24 is wrong, it should be 8 (48/6 = 8).
[B].
[C].
[D].
Answer: Option C
Explanation:
The terms are successively divided by 12, 10, 8, 6, …etc.
So, 24 is wrong, it should be 8 (48/6 = 8).
[B].
[C].
[D].
Answer: Option A
Explanation:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
[B].
[C].
[D].
Answer: Option A
Explanation:
80 = 2 x 5 x 8
Since 653xy is divisible by 2 and 5 both, so y = 0.
Now, 653x is divisible by 8, so 13x should be divisible by 8.
This happens when x = 6.
x + y = (6 + 0) = 6.
[B].
[C].
[D].
Answer: Option A
Explanation:
Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
| 140 | x 5x | , | 150 | x 7x | and | 175 | x 8x | |||||||
| 100 | 100 | 100 | 
| 7x, | 21x | and 14x. | 
| 2 | 
| The required ratio = 7x : | 21x | : 14x | 
| 2 | 
14x : 21x : 28x
2 : 3 : 4.
[B].
[C].
[D].
Answer: Option D
Explanation:
28 May, 2006 = (2005 years + Period from 1.1.2006 to 28.5.2006)
Odd days in 1600 years = 0
Odd days in 400 years = 0
5 years = (4 ordinary years + 1 leap year) = (4 x 1 + 1 x 2) 6 odd days
Jan.  Feb.   March    April    May
(31 +  28  +  31   +   30   +   28 ) = 148 days
148 days = (21 weeks + 1 day) 1 odd day.
Total number of odd days = (0 + 0 + 6 + 1) = 7 0 odd day.
Given day is Sunday.
[B].
[C].
[D].
Answer: Option C
Explanation:
Let the number of students in rooms A and B be x and y respectively.
Then, x – 10 = y + 10 x – y = 20 …. (i)
and x + 20 = 2(y – 20) x – 2y = -60 …. (ii)
Solving (i) and (ii) we get: x = 100 , y = 80.
The required answer A = 100.
		A. 7 years
B. 10 years
C. 15 years
D. 20 years
Explanation:
P(1 + R/100)5 = 2P => (1 + R/100)5 = 2
Let P(1 + R/100)n = 8P
=> (1 + R/100)n = 8 = 23 = {(1 + R/100)5}3
=> (1 + R/100)n = (1 + R/100)15 => n = 15 Required time = 15 years.