4, -8, 16, -32, 64, (….)
4, -8, 16, -32, 64, (….)
[A].
[B].
[C].
[D].
Answer: Option B
Explanation:
Each number is the proceeding number multiplied by -2.
So, the required number is -128.
[B].
[C].
[D].
Answer: Option B
Explanation:
Each number is the proceeding number multiplied by -2.
So, the required number is -128.
[B].
[C].
[D].
Answer: Option B
Explanation:
P.W. = Rs. (540 – 90) = Rs. 450.
S.I. on Rs. 450 = Rs. 90.
| S.I. on Rs. 540 = Rs. | 90 | x 540 | = Rs. 108. | ||
| 450 | 
B.D. = Rs. 108.
		A. Rs. 8600
B. Rs. 8620
C. Rs. 8800
D. Rs. 8840
E. None of these
Explanation:
Amount = [8000 * (1 + 5/100)2]
= 8000 * 21/20 * 21/20
= Rs. 8820
[B].
[C].
[D].
Answer: Option C
Explanation:
log 27 = 1.431
log (33 ) = 1.431
3 log 3 = 1.431
log 3 = 0.477
log 9 = log(32 ) = 2 log 3 = (2 x 0.477) = 0.954.
		A. Rs 230
B. Rs 232
C. Rs 600
D. Rs 832
Explanation:
S.I = Rs (6000 × 5/100 × 2) = Rs 600
C.I = Rs [5000 × (1 + 8/100)2 – 5000]
= Rs (5000 × 27/25 × 27/25 – 5000)
= Rs(5832 – 5000)
= Rs 832
(C.I) – (S.I) = Rs (832 – 600) = Rs 232
[B].
[C].
[D].
Answer: Option C
Explanation:
Let the speed of the train be x km/hr and that of the car be y km/hr.
| Then, | 120 | + | 480 | = 8 | 1 | + | 4 | = | 1 | ….(i) | 
| x | y | x | y | 15 | 
| And, | 200 | + | 400 | = | 25 | 1 | + | 2 | = | 1 | ….(ii) | |
| x | y | 3 | x | y | 24 | 
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4.
[B].
[C].
[D].
Answer: Option C
Explanation:
Money collected = (59.29 x 100) paise = 5929 paise.
Number of members = 5929 = 77.