(?) + 3699 + 1985 – 2047 = 31111
[A].
[B].
[C].
[D].
Answer: Option B
Explanation:
x + 3699 + 1985 – 2047 = 31111
x + 3699 + 1985 = 31111 + 2047
x + 5684 = 33158
x = 33158 – 5684 = 27474.
[B].
[C].
[D].
Answer: Option A
Explanation:
The year 2004 is a leap year. So, it has 2 odd days.
But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.
The day on 6th March, 2005 will be 1 day beyond the day on 6th March, 2004.
Given that, 6th March, 2005 is Monday.
6th March, 2004 is Sunday (1 day before to 6th March, 2005).
[B].
| 9 | 3 | % stock at 117 | 
| 4 | 
[C].
[D].
Answer: Option B
Explanation:
Let investment in each case be Rs. (143 x 117).
| Income in 1st case = Rs. | 11 | x 143 x 117 | = Rs. 1287. | ||
| 143 | 
| Income in 2nd case = Rs. | 39 | x 143 x 117 | = Rs. 1394.25 | ||
| 4 x 117 | 
| Clearly, 9 | 3 | % stock at 117 is better. | 
| 4 | 
[B].
[C].
[D].
Answer: Option B
Explanation:
| 4 | A | = | 2 | B | |
| 15 | 5 | 
| A = | 2 | x | 15 | B | |
| 5 | 4 | 
| A = | 3 | B | 
| 2 | 
| A | = | 3 | |
| B | 2 | 
A : B = 3 : 2.
| B’s share = Rs. | 1210 x | 2 | = Rs. 484. | ||
| 5 | 
[B].
[C].
| 50 | 4 | min. past 4 | 
| 11 | 
[D].
| 54 | 6 | min. past 4 | 
| 11 | 
Answer: Option D
Explanation:
At 4 o’clock, the hands of the watch are 20 min. spaces apart.
To be in opposite directions, they must be 30 min. spaces apart.
Minute hand will have to gain 50 min. spaces.
55 min. spaces are gained in 60 min.
| 50 min. spaces are gained in | 60 | x 50 | min. or 54 | 6 | min. | |
| 55 | 11 | 
| Required time = 54 | 6 | min. past 4. | 
| 11 | 
[B].
[C].
[D].
Answer: Option C
Explanation:
Then number 6×2 must be divisible by 8.
x = 3, as 632 is divisible 8.
| 21 | 
| 46 | 
[B].
| 25 | 
| 117 | 
[C].
| 1 | 
| 50 | 
[D].
| 3 | 
| 25 | 
Answer: Option A
Explanation:
Let S be the sample space and E be the event of selecting 1 girl and 2 boys.
| Then, n(S) | = Number ways of selecting 3 students out of 25 | |||
| = 25C3 ` | ||||
| 
 | ||||
| = 2300. | 
| n(E) | = (10C1 x 15C2) | ||||||
| 
 | |||||||
| = 1050. | 
| P(E) = | n(E) | = | 1050 | = | 21 | . | 
| n(S) | 2300 | 46 |