[B].
[C].
[D].
Answer: Option A
Explanation:
Let the present ages of Sameer and Anand be 5x years and 4x years respectively.
| Then, | 5x + 3 | = | 11 |
| 4x + 3 | 9 |
9(5x + 3) = 11(4x + 3)
45x + 27 = 44x + 33
45x – 44x = 33 – 27
x = 6.
Anand’s present age = 4x = 24 years.
| 59 | 7 | min. past 3 |
| 12 |
[B].
[C].
| 58 | 7 | min. past 3 |
| 11 |
[D].
| 2 | 3 | min. past 4 |
| 11 |
Answer: Option B
Explanation:
| Time from 7 a.m. to 4.15 p.m. = 9 hrs 15 min. = | 37 | hrs. |
| 4 |
3 min. 5 sec. of this clock = 3 min. of the correct clock.
| 37 | hrs of this clock = | 1 | hrs of the correct clock. | |
| 720 | 20 |
| 37 | hrs of this clock = | 1 | x | 720 | x | 37 | hrs of the correct clock. | |||
| 4 | 20 | 37 | 4 |
= 9 hrs of the correct clock.
The correct time is 9 hrs after 7 a.m. i.e., 4 p.m.
[B].
[C].
[D].
Answer: Option C
Explanation:
| Number of pages typed by Ravi in 1 hour = | 32 | = | 16 | . |
| 6 | 3 |
| Number of pages typed by Kumar in 1 hour = | 40 | = 8. |
| 5 |
| Number of pages typed by both in 1 hour = | 16 | + 8 | = | 40 | . | ||
| 3 | 3 |
| Time taken by both to type 110 pages = | 110 x | 3 | hours | ||
| 40 |
| = 8 | 1 | hours (or) 8 hours 15 minutes. |
| 4 |
[B].
[C].
[D].
Answer: Option C
Explanation:
(xn + 1) will be divisible by (x + 1) only when n is odd.
(6767 + 1) will be divisible by (67 + 1)
(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the thickness of the bottom be x cm.
Then, [(330 – 10) x (260 – 10) x (110 – x)] = 8000 x 1000
320 x 250 x (110 – x) = 8000 x 1000
| (110 – x) = | 8000 x 1000 | = 100 |
| 320 x 250 |
x = 10 cm = 1 dm.
A. Rs.140
B. Rs.120
C. Rs.130
D. Rs.110
E. None of these.