26.98% of 6002 + 45.01% of 4199 = ________?
		A. 2500
B. 3500
C. 3600
D. 4500
Explanation:
27% of 6000 + 45% of 4200 = ?
=> ? = 27/100 * 6000 + 45/100 * 4200
=> ? = 1620 + 1890 = 3510 = 3500
		A. 2500
B. 3500
C. 3600
D. 4500
Explanation:
27% of 6000 + 45% of 4200 = ?
=> ? = 27/100 * 6000 + 45/100 * 4200
=> ? = 1620 + 1890 = 3510 = 3500
		A. 7/8
B. 13/16
C. 31/40
D. 63/80
Explanation:
L.C.M of 8, 16, 40 and 80 = 80.
7/8 = 70/80; 13/16 = 65/80; 31/40 = 62/80
Since, 70/80 > 63/80 > 65/80 > 62/80,
So, 7/8 > 63/80 > 13/16 > 31/40
So, 7/8 is the largest.
		A. 2:5
B. 5:3
C. 3:5
D. 1:2
X ———— Y ———— Z
If ‘d’ is the distance between X and Y, then ‘d’ is the distance between Y and Z.
Now the total time for the batsman to row from X to Z is 4 hours. Therefore, time to row from X to Y is 2 hours.
Also the time for the boats man to row from X to Y and back is 10 hours. Hence, time required to row from Y to X is 8 hours.
If, a: speed of boats man in still water
b: speed of the river
d/(a + b) = 2; d/(a – b) = 8
2*(a + b) = 8*(a – b)
a + b = 4a – 4b
3a = 5b
a:b = 5:3
		A. 700,400
B. 820,360
C. 800,500
D. 820,369
		A. 12
B. 18
C. 20
D. 30
Explanation:
36 * 48 / 64 + 36/12 = 27 + 3 = 30
		A. Rs. 270
B. Rs. 290
C. Rs. 300
D. None of these
Explanation:
Marked price be Rs. X
 Discount availed by the retailer = 15% of Rs. X
C.P of the machine by the retailer
= (X – 15% of X) = Rs. 17X/20
15% of 17X/20 = 1955 – 17X/20
51X/400 + 17X/20 = 1955 or
X = 2000 Discount received retailer
= (15% of Rs. 2000) = Rs. 300
		A. 140
B. 156
C. 175
D. 214
Given that the area of the square = 1225 sq.units
=> Side of square = √1225 = 35 units
The radius of the circle = side of the square = 35 units Length of the rectangle = 2/5 * 35 = 14 units
Given that breadth = 10 units
Area of the rectangle = lb = 14 * 10 = 140 sq.units