2222.2 + 222.22 + 22.222 = ________?
2222.2 + 222.22 + 22.222 = ________?
A. 2466.462
B. 2664.642
C. 2464.462
D. 2466.642
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By selling an umbrella for Rs. 300, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is:________?
By selling an umbrella for Rs. 300, a shop keeper gains 20%. During a clearance sale, the shopkeeper allows a discount of 10% on the marked price. His gain percent during the sale is:________?A. 7
B. 7.5
C. 8
D. 9
Explanation:
Marked price = Rs. 300
C.P. = 100/120 * 300 = Rs. 250
Sale price = 90% of Rs. 300 = Rs. 270
Required gain % = 20/250 * 100 = 8%.Two cylinders are of the same height. Their radii are in the ratio 1: 3. If the volume of the first cylinder is 40 cc. Find the volume of the second cylinder?
Two cylinders are of the same height. Their radii are in the ratio 1: 3. If the volume of the first cylinder is 40 cc. Find the volume of the second cylinder?A. 360 cc
B. 60 cc
C. 300 cc
D. 36 cc
r1 = x r2 = 3x
Π * x2 * h = 40
Π9 x2h = 40 * 9 = 360A rectangular carpet has an area of 120 square meters and a parameter of 46m. The length of it’s diagonals is_________?
A rectangular carpet has an area of 120 square meters and a parameter of 46m. The length of it’s diagonals is_________?A. 11m
B. 13m
C. 15m
D. 17mThe sum of five consecutive even numbers of set x is 440. Find the sum of a different set of five consecutive integers whose second least number is 121 less than double the least number of set x?
The sum of five consecutive even numbers of set x is 440. Find the sum of a different set of five consecutive integers whose second least number is 121 less than double the least number of set x?A. 248
B. 240
C. 228
D. 236
E. None of these
Explanation:
Let the five consecutive even numbers be 2(x – 2), 2(x – 1), 2x, 2(x + 1) and 2(x + 2)
Their sum = 10x = 440
x = 44 => 2(x – 2) = 84
Second least number of the other set = 2(84) – 121 = 47
This set has its least number as 46.
Sum of the numbers of this set = 46 + 47 + 48 + 49 + 50
= 48 – 2 + 48 – 1 + 48 + 48 + 1 + 48 + 2 => 5(48) = 240Fresh grapes contain 80 % water dry grapes contain 10 % water. If the weight of dry grapes is 250 kg. What was its total weight when it was fresh?
Fresh grapes contain 80 % water dry grapes contain 10 % water. If the weight of dry grapes is 250 kg. What was its total weight when it was fresh?A. 1000 kg
B. 1100 kg
C. 1125 kg
D. 1225 kg
Explanation:
Let the weight of fresh grapes be x kg
Quantity of water in it = (80/100 × x)kg = 4x/5 kg
Quantity of pulp in it = (x – 4x/5)kg = x/5 kg
Quantity of water in 250 kg dry grapes
= (10/100 × 250)kg = 25kg
Quantity of pulp in it = (250 – 25)kg = 225 kg
Therefore, x/5 = 225
=> x = 1125A and B can do a piece of work in 12 days; B and C in 15 days; C and A in 20 days. A alone can do the work in__________?
A and B can do a piece of work in 12 days; B and C in 15 days; C and A in 20 days. A alone can do the work in__________?A. 20 days
B. 30 days
C. 40 days
D. none of these