[B].
[C].
[D].
Answer: Option B
Explanation:
Each number is double the preceding one plus 1.
So, the next number is (255 x 2) + 1 = 511.
[B].
[C].
[D].
Answer: Option C
Explanation:
(xn + 1) will be divisible by (x + 1) only when n is odd.
(6767 + 1) will be divisible by (67 + 1)
(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
[B].
[C].
[D].
Answer: Option D
Explanation:
| T.D. = | B.G. x 100 | = Rs. | 6 x 100 | = Rs. 50. | ||
| R x T | 12 x 1 |
[B].
[C].
[D].
Answer: Option E
Explanation:
A x 2 + 1, B x 3 + 1, C x 2 + 1, D x 3 + 1 and so on.
So, 356 is wrong.
[B].
[C].
[D].
Answer: Option C
Explanation:
Let the speed of the train be x km/hr and that of the car be y km/hr.
| Then, | 120 | + | 480 | = 8 | 1 | + | 4 | = | 1 | ….(i) |
| x | y | x | y | 15 |
| And, | 200 | + | 400 | = | 25 | 1 | + | 2 | = | 1 | ….(ii) | |
| x | y | 3 | x | y | 24 |
Solving (i) and (ii), we get: x = 60 and y = 80.
Ratio of speeds = 60 : 80 = 3 : 4.
A. Rs. 2160
B. Rs. 3120
C. Rs. 3972
D. Rs. 6240
Explanation:
Let P = Rs. 100. Then, S.I. Rs. 60 and T = 6 years.
R = (100 * 60)/(100 * 6) = 10% p.a.
Now, P = Rs. 12000, T = 3 years and R = 10% p.a.
C.I. = [12000 * {(1 + 10/100)3 – 1}]
= 12000 * 331/1000 = Rs. 3972
A. 8 kmph
B. 4 kmph
C. 2 kmph
D. 10 kmph
Explanation:
M = 45
S = 1.5
DS = 6
US = 3
AS = (2 * 6 * 3) /9 = 4