| 1 |
| 2 |
[B].
| 3 |
| 4 |
[C].
| 3 |
| 8 |
[D].
| 5 |
| 16 |
Answer: Option B
Explanation:
In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
| Then, E | = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)} |
n(E) = 27.
| P(E) = | n(E) | = | 27 | = | 3 | . |
| n(S) | 36 | 4 |
A. Rs 4500
B. Rs 5000
C. Rs 5500
D. Rs 6000
Explanation:
Let the money borrowed be Rs x
Interest paid by the money lender = Rs (x × 4/100 × 1) =Rs x/25
Interest received by the money lender
= Rs [x × (1 + 3/100)2 – x]
= Rs(x × 103/100 × 103/100 – x)
Gain = Rs (609x/1000 – x /25)
= Rs 209x/1000 = Rs 609x/10000
Therefore 209x/10000 = 104.50
=> 209x = 1045000
=> x = 5000
Hence money borrowed = Rs 5000
[B].
[C].
[D].
Answer: Option B
Explanation:
| 2 kmph = | 2 x | 5 | m/sec = | 5 | m/sec. | ||
| 18 | 9 |
| 4 kmph = | 4 x | 5 | m/sec = | 10 | m/sec. | ||
| 18 | 9 |
Let the length of the train be x metres and its speed by y m/sec.
| Then, | x | = 9 and | x | = 10. | ||||
|
|
9y – 5 = x and 10(9y – 10) = 9x
9y – x = 5 and 90y – 9x = 100.
On solving, we get: x = 50.
Length of the train is 50 m.
[B].
[C].
[D].
Answer: Option D
Explanation:
Let B’s capital be Rs. x.
| Then, | 3500 x 12 | = | 2 | ||
| 7x | 3 |
14x = 126000
x = 9000.
[B].
[C].
[D].
Answer: Option D
Explanation:
Let the number be x and on dividing x by 5, we get k as quotient and 3 as remainder.
x = 5k + 3
x2 = (5k + 3)2
= (25k2 + 30k + 9)
= 5(5k2 + 6k + 1) + 4
On dividing x2 by 5, we get 4 as remainder.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the required number of days be x.
Less persons, More days (Indirect Proportion)
More working hours per day, Less days (Indirect Proportion)
| Persons | 30 | : | 39 | :: 12 : x | |
| Working hours/day | 6 | : | 5 |
30 x 6 x x = 39 x 5 x 12
| x = | (39 x 5 x 12) |
| (30 x 6) |
x = 13.