12(13/18) + 16(11/27) – 10(5/9) = _________?
		A. 182/3
B. 1831/54
C. 18
D. 201/2
Explanation:
12 + 16 – 10 = 18
and 13/18 + 11/27 – 5/9 = (39 + 22 – 30)/(9 * 2 * 3) = 31/54 The answer is 18 (31/54)
		A. 182/3
B. 1831/54
C. 18
D. 201/2
Explanation:
12 + 16 – 10 = 18
and 13/18 + 11/27 – 5/9 = (39 + 22 – 30)/(9 * 2 * 3) = 31/54 The answer is 18 (31/54)
		A. 200m
B. 210m
C. 220m
D. 185m
		A. Rs. 1550
B. Rs. 1650
C. Rs. 1750
D. Rs. 2000
Explanation:
C.I. = [4000 * (1 + 10/100)2 – 4000]
= (4000 * 11/10 * 11/10 – 4000) = Rs. 840.
Sum = (420 * 100)/(3 * 8) = Rs. 1750
		A. Rs. 12
B. Rs. 12.96
C. Rs. 14.40
D. None of these
Explanation:
90 : 10.80 :: 120 : x
X = (10.80 ×120)/90 = 14.40
Hence, the toy must be sold for Rs. 14.40
		A. 20%
B. 25 %
C. 28%
D. 30%
Explanation:
20 % of x + 30 = 32 % of x – 42
Or 12 % of x = 72.
So, x = (72 ×100)/12 = 600
Pass marks = 20 % of 600 + 30 = 150
Pass Percentage =[1/4 x 100]%= 25 %
		A. 5
B. 8
C. 10
D. 15
Explanation:
He buys 12 oranges,
Then S.P = Rs. 1
 Now, 80 : 1 :: 120 : X
 X = 1 × 120/80 = 3/2 Rs. 3/2,
oranges sold = 12 Rs. 1,
oranges sold = (12 × 2/3) = 8
		A. 10 %
B. 12 %
C. 6 %
D. 8 %
Explanation:
5000 × (1 +R/100) 2 – 5000 –(10000R/100)= 72
=> 5000 [(1 + R/100) 2 – 1 – R/50] = 72
=> 1 + R2/100 + 2R/100 – 1 – R/50 = 72/5000
=> R2 = (72/5000 × 10000) = 144 or R =12%