(12 + 22 + 32 + … + 102) = ?

Question:
(12 + 22 + 32 + … + 102) = ?

[A].

330

[B].

345

[C].

365

[D].

385

Answer: Option D

Explanation:

We know that (12 + 22 + 32 + … + n2) =	1	n(n + 1)(2n + 1)
	6

Putting n = 10, required sum =		1	x 10 x 11 x 21		= 385
		6