[B].
[C].
[D].
Answer: Option C
Explanation:
(xn + 1) will be divisible by (x + 1) only when n is odd.
(6767 + 1) will be divisible by (67 + 1)
(6767 + 1) + 66, when divided by 68 will give 66 as remainder.
[B].
[C].
[D].
Answer: Option D
Explanation:
| Amount of Rs. 100 for 1 year when compounded half-yearly |
= Rs. | 100 x | 1 + | 3 | 2 | = Rs. 106.09 | |||||
| 100 |
Effective rate = (106.09 – 100)% = 6.09%
[B].
[C].
[D].
| 7 | 1 |
| 2 |
Answer: Option B
Explanation:
| Work done = | 5 |
| 8 |
| Balance work = | 1 – | 5 | = | 3 | ||
| 8 | 8 |
Let the required number of days be x.
| Then, | 5 | : | 3 | = :: 10 : x | 5 | x x = | 3 | x 10 | |
| 8 | 8 | 8 | 8 |
| x = | 3 | x 10 x | 8 | ||
| 8 | 5 |
x = 6.
| 1 |
| 10 |
[B].
| 2 |
| 5 |
[C].
| 2 |
| 7 |
[D].
| 5 |
| 7 |
Answer: Option C
Explanation:
| P (getting a prize) = | 10 | = | 10 | = | 2 | . |
| (10 + 25) | 35 | 7 |
[B].
[C].
[D].
Answer: Option E
Explanation:
Let breadth = x metres.
Then, length = (x + 20) metres.
| Perimeter = | 5300 | m = 200 m. | ||
| 26.50 |
2[(x + 20) + x] = 200
2x + 20 = 100
2x = 80
x = 40.
Hence, length = x + 20 = 60 m.
[B].
[C].
| 50 | 4 | min. past 4 |
| 11 |
[D].
| 54 | 6 | min. past 4 |
| 11 |
Answer: Option D
Explanation:
At 4 o’clock, the hands of the watch are 20 min. spaces apart.
To be in opposite directions, they must be 30 min. spaces apart.
Minute hand will have to gain 50 min. spaces.
55 min. spaces are gained in 60 min.
| 50 min. spaces are gained in | 60 | x 50 | min. or 54 | 6 | min. | |
| 55 | 11 |
| Required time = 54 | 6 | min. past 4. |
| 11 |