[B].
[C].
[D].
Answer: Option A
Explanation:
Numbers are all primes. The next prime is 43.
[B].
[C].
[D].
Answer: Option A
Explanation:
| 106 x 106 – 94 x 94 | = (106)2 – (94)2 |
| = (106 + 94)(106 – 94) [Ref: (a2 – b2) = (a + b)(a – b)] | |
| = (200 x 12) | |
| = 2400. |
[B].
[C].
[D].
Answer: Option A
Explanation:
Let the total number of shots be x. Then,
| Shots fired by A = | 5 | x |
| 8 |
| Shots fired by B = | 3 | x |
| 8 |
| Killing shots by A = | 1 | of | 5 | x | = | 5 | x |
| 3 | 8 | 24 |
| Shots missed by B = | 1 | of | 3 | x | = | 3 | x |
| 2 | 8 | 16 |
| 3x | = 27 or x = | 27 x 16 | = 144. | |||
| 16 | 3 |
| Birds killed by A = | 5x | = | 5 | x 144 | = 30. | ||
| 24 | 24 |
| 1 |
| 2 |
[B].
| 3 |
| 4 |
[C].
| 3 |
| 8 |
[D].
| 5 |
| 16 |
Answer: Option B
Explanation:
In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
| Then, E | = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)} |
n(E) = 27.
| P(E) = | n(E) | = | 27 | = | 3 | . |
| n(S) | 36 | 4 |
[B].
[C].
[D].
Answer: Option A
Explanation:
Clearly, (2272 – 875) = 1397, is exactly divisible by N.
Now, 1397 = 11 x 127
The required 3-digit number is 127, the sum of whose digits is 10.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let 0.0169 x x = 1.3.
Then, 0.0169x = (1.3)2 = 1.69
| x = | 1.69 | = 100 |
| 0.0169 |
[B].
[C].
[D].
Answer: Option A
Explanation:
Let the length of the first train be x metres.
| Then, the length of the second train is | x | metres. | ||
| 2 |
| Relative speed = (48 + 42) kmph = | 90 x | 5 | m/sec = 25 m/sec. | ||
| 18 |
| [x + (x/2)] | = 12 or | 3x | = 300 or x = 200. | |
| 25 | 2 |
Length of first train = 200 m.
Let the length of platform be y metres.
| Speed of the first train = | 48 x | 5 | m/sec = | 40 | m/sec. | ||
| 18 | 3 |
| (200 + y) x | 3 | = 45 |
| 40 |
600 + 3y = 1800
y = 400 m.