A. 4km
B. 6 km
C. 8 km
D. 12 km
Explanation:
Speed downstream = (9+3) km/hr = 12km/hr
Speed upstream = (9-3) km/hr = 6 km/hr
Distance AB = x km
x/6 + x/12 = 3
=> 2x + x = 36
=> x= 12
[B].
[C].
[D].
Answer: Option B
Explanation:
Subtract 1, 3, 5, 7, 9, 11 from successive numbers.
So, 34 is wrong.
[B].
[C].
[D].
Answer: Option A
Explanation:
Speed downstream = (5 + 1) kmph = 6 kmph.
Speed upstream = (5 – 1) kmph = 4 kmph.
Let the required distance be x km.
| Then, | x | + | x | = 1 |
| 6 | 4 |
2x + 3x = 12
5x = 12
x = 2.4 km.
[B].
[C].
[D].
Answer: Option D
Explanation:
| For an income of Re. 1 in 9% stock at 96, investment = Rs. | 96 | = Rs. | 32 | ||
| 9 | 3 |
| For an income Re. 1 in 12% stock at 120, investment = Rs. | 120 | = Rs. 10. | ||
| 12 |
| Ratio of investments = | 32 | : 10 = 32 : 30 = 16 : 15. |
| 3 |
[B].
[C].
[D].
Answer: Option C
Explanation:
There are 6 letters in the given word, out of which there are 3 vowels and 3 consonants.
Let us mark these positions as under:
(1) (2) (3) (4) (5) (6)
Now, 3 vowels can be placed at any of the three places out 4, marked 1, 3, 5.
Number of ways of arranging the vowels = 3P3 = 3! = 6.
Also, the 3 consonants can be arranged at the remaining 3 positions.
Number of ways of these arrangements = 3P3 = 3! = 6.
Total number of ways = (6 x 6) = 36.
A. 18
B. 12
C. 9
D. 6