106 x 106 – 94 x 94 = ?
106 x 106 – 94 x 94 = ?
[A].
[B].
[C].
[D].
Answer: Option A
Explanation:
| 106 x 106 – 94 x 94 | = (106)2 – (94)2 | 
| = (106 + 94)(106 – 94) [Ref: (a2 – b2) = (a + b)(a – b)] | |
| = (200 x 12) | |
| = 2400. | 
[B].
[C].
[D].
Answer: Option B
Explanation:
| Suppose A, B and C take x, | x | and | x | days respectively to finish the work. | 
| 2 | 3 | 
| Then, | 1 | + | 2 | + | 3 | = | 1 | ||
| x | x | x | 2 | 
| 6 | = | 1 | |
| x | 2 | 
x = 12.
So, B takes (12/2) = 6 days to finish the work.
[B].
[C].
[D].
Answer: Option B
Explanation:
The smallest 5-digit number = 10000.
 41) 10000 (243
     82
     —
     180
     164
     —-
      160
      123
      —
       37
      — 
 Required number = 10000 + (41 – 37)
                 = 10004.      
[B].
[C].
[D].
Answer: Option D
Explanation:
Since the month begins with a Sunday, to there will be five Sundays in the month.
| Required average | 
 | |||||
| 
 | ||||||
| = 285 | 
[B].
[C].
[D].
Answer: Option A
Explanation:
| Given Exp. = | (12)3 x 64 | = | (12)3 x 64 | = (12)2 x 62 = (72)2 = 5184 | 
| 432 | 12 x 62 | 
		A. Rs. 400
B. Rs. 450
C. Rs. 460
D. Rs. 480
Explanation:
Let the sum be Rs. P. Then,
[P(1 + 25/(2 * 100))2 – P] = 510
P[(9/8)2 – 1] = 510.
Sum = Rs. 1920
So, S.I. = (1920 * 25 * 2) / (2 * 100) = Rs. 480
[B].
[C].
[D].
Answer: Option D
Explanation:
Let the two consecutive odd integers be (2n + 1) and (2n + 3). Then,
(2n + 3)2 – (2n + 1)2 = (2n + 3 + 2n + 1) (2n + 3 – 2n – 1)
= (4n + 4) x 2
= 8(n + 1), which is divisible by 8.