1 Kcal/kg. °C is equivalent to _______________ BTU/lb. °F ?
1 Kcal/kg. °C is equivalent to _______________ BTU/lb. °F ?
		A. 1
B. 2.42
C. 4.97
D. None of these
		A. 1
B. 2.42
C. 4.97
D. None of these
		A. The solvent begins to freeze out even before
B. It will undergo no change until
C. It will not solidify even on
D. None of these
		A. T
B. T0.5
C. T1.5
D. T2
		A. PV = RT + B/V + y/V2 + ….
B. (P + a/V2)(V-b) = RT
C. loge (p/p0) = (λ/R) (1/T0 – 1/T)
D. p = [RT/(V – b)] – (a/TV2)
		A. A2 is more alkaline than solution A2
B. A1 is highly acidic
C. A1 is very slightly acidic
D. Both A. & C.
		A. 1 atm
B. 10 torr
C. 0.98 Pascal
D. 1 kgf/cm2
		A. Nature of the solute
B. Nature of the solvent
C. Temperature
D. Pressure