1, 4, 9, 16, 20, 36, 49
1, 4, 9, 16, 20, 36, 49
[A].
[B].
[C].
[D].
Answer: Option C
Explanation:
The pattern is 12, 22, 32, 42, 52, 62, 72. But, instead of 52, it is 20 which to be turned out.
[B].
[C].
[D].
Answer: Option C
Explanation:
The pattern is 12, 22, 32, 42, 52, 62, 72. But, instead of 52, it is 20 which to be turned out.
[B].
[C].
[D].
Answer: Option B
Explanation:
Let the middle digit be x.
Then, 2x = 10 or x = 5. So, the number is either 253 or 352.
Since the number increases on reversing the digits, so the hundred’s digits is smaller than the unit’s digit.
Hence, required number = 253.
[B].
[C].
[D].
Answer: Option C
Explanation:
S.I. for 1 year = Rs. (854 – 815) = Rs. 39.
S.I. for 3 years = Rs.(39 x 3) = Rs. 117.
Principal = Rs. (815 – 117) = Rs. 698.
		A. 1875/2029
B. 1/2.5
C. 1903/2156
D. 4/9
		A. 3.5km/hr
B. 5.75km/hr
C. 6.5km/hr
D. 7km/hr
Explanation:
Speed Downstream = 15.5 km/hr,
speed upstream = 8.5 km/hr
Speed of the stream = ½ (15.5 – 8.5)km = 3.5 km/hr
[B].
| 22 | 1 | days | 
| 2 | 
[C].
[D].
Answer: Option B
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 – 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
| If difference of time is 60 days, B takes | 3 | x 60 | = 90 days. | ||
| 2 | 
So, A takes 30 days to do the work.
| A’s 1 day’s work = | 1 | 
| 30 | 
| B’s 1 day’s work = | 1 | 
| 90 | 
| (A + B)’s 1 day’s work = | 1 | + | 1 | = | 4 | = | 2 | ||
| 30 | 90 | 90 | 45 | 
| A and B together can do the work in | 45 | = 22 | 1 | days. | 
| 2 | 2 | 
[B].
[C].
[D].
Answer: Option C
Explanation:
Speed of train relative to jogger = (45 – 9) km/hr = 36 km/hr.
| = | 36 x | 5 | m/sec | |
| 18 | 
= 10 m/sec.
Distance to be covered = (240 + 120) m = 360 m.
| Time taken = | 360 | sec | = 36 sec. | |
| 10 |