[B].
[C].
[D].
Answer: Option B
Explanation:
1, 1 + 12 = 2, 2 + 22 = 6, 6 + 32 = 15, 15 + 42 = 31, 31 + 52 = 56, 56 + 62 = 92
Last number of given series must be 92 not 91.
[B].
[C].
[D].
Answer: Option B
Explanation:
(6n2 + 6n) = 6n(n + 1), which is always divisible by 6 and 12 both, since n(n + 1) is always even.
| 12 |
| 35 |
[B].
| 1 |
| 35 |
[C].
| 35 |
| 8 |
[D].
| 7 |
| 32 |
Answer: Option A
Explanation:
Let the numbers be a and b. Then, a + b = 12 and ab = 35.
| a + b | = | 12 | 1 | + | 1 | = | 12 | ||||
| ab | 35 | b | a | 35 |
| Sum of reciprocals of given numbers = | 12 |
| 35 |
| 1 |
| 8 |
[B].
[C].
[D].
Answer: Option B
Explanation:
Let log2 16 = n.
Then, 2n = 16 = 24 n = 4.
log2 16 = 4.
[B].
[C].
| 50 | 4 | min. past 4 |
| 11 |
[D].
| 54 | 6 | min. past 4 |
| 11 |
Answer: Option D
Explanation:
At 4 o’clock, the hands of the watch are 20 min. spaces apart.
To be in opposite directions, they must be 30 min. spaces apart.
Minute hand will have to gain 50 min. spaces.
55 min. spaces are gained in 60 min.
| 50 min. spaces are gained in | 60 | x 50 | min. or 54 | 6 | min. | |
| 55 | 11 |
| Required time = 54 | 6 | min. past 4. |
| 11 |
[B].
[C].
[D].
Answer: Option C
Explanation:
| Area to be plastered | = [2(l + b) x h] + (l x b) |
| = {[2(25 + 12) x 6] + (25 x 12)} m2 | |
| = (444 + 300) m2 | |
| = 744 m2. |
| Cost of plastering = Rs. | 744 x | 75 | = Rs. 558. | ||
| 100 |
[B].
[C].
[D].
Answer: Option A
Explanation:
Let the average age of the whole team by x years.
11x – (26 + 29) = 9(x -1)
11x – 9x = 46
2x = 46
x = 23.
So, average age of the team is 23 years.