0.002 x 0.5 = ?
Question:
0.002 x 0.5 = ?
[A].
0.0001
0.001
0.01
0.1
0.002 x 0.5 = ?
[A].
[B].
[C].
[D].
Answer: Option B
Explanation:
2 x 5 = 10.
Sum of decimal places = 4
0.002 x 0.5 = 0.001
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A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
Question: A is two years older than B who is twice as old as C. If the total of the ages of A, B and C be 27, then how old is B?
[A].7 [B].
8 [C].
9 [D].
10 Answer: Option D
Explanation:
Let C’s age be x years. Then, B’s age = 2x years. A’s age = (2x + 2) years.
(2x + 2) + 2x + x = 27
5x = 25
x = 5.
Hence, B’s age = 2x = 10 years.
How many of the following numbers are divisible by 3 but not by 9 ? 2133, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276
Question: How many of the following numbers are divisible by 3 but not by 9 ?
2133, 2343, 3474, 4131, 5286, 5340, 6336, 7347, 8115, 9276
[A].5 [B].
6 [C].
7 [D].
None of these Answer: Option B
Explanation:
Marking (/) those which are are divisible by 3 by not by 9 and the others by (X), by taking the sum of digits, we get:s
2133 9 (X)
2343 12 (/)
3474 18 (X)
4131 9 (X)
5286 21 (/)
5340 12 (/)
6336 18 (X)
7347 21 (/)
8115 15 (/)
9276 24 (/)
Required number of numbers = 6.
A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
Question: A is thrice as good as workman as B and therefore is able to finish a job in 60 days less than B. Working together, they can do it in:
[A].20 days [B].
22 1 days 2 [C].
25 days [D].
30 days Answer: Option B
Explanation:
Ratio of times taken by A and B = 1 : 3.
The time difference is (3 – 1) 2 days while B take 3 days and A takes 1 day.
If difference of time is 2 days, B takes 3 days.
If difference of time is 60 days, B takes 3 x 60 = 90 days. 2 So, A takes 30 days to do the work.
A’s 1 day’s work = 1 30 B’s 1 day’s work = 1 90 (A + B)’s 1 day’s work = 1 + 1 = 4 = 2 30 90 90 45 A and B together can do the work in 45 = 22 1 days. 2 2 In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is of the number of students of 8 years of age which is 48. What is the total number of students in the school?
Question: In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is of the number of students of 8 years of age which is 48. What is the total number of students in the school?
[A].72 [B].
80 [C].
120 [D].
150 Answer: Option E
Explanation:
Let the number of students be x. Then,
Number of students above 8 years of age = (100 – 20)% of x = 80% of x.
80% of x = 48 + 2 of 48 3 80 x = 80 100 x = 100.
Video Explanation: https://youtu.be/yPfocU6DA2M
Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar’s age at present?
Question: Six years ago, the ratio of the ages of Kunal and Sagar was 6 : 5. Four years hence, the ratio of their ages will be 11 : 10. What is Sagar’s age at present?
[A].16 years [B].
18 years [C].
20 years [D].
Cannot be determined Answer: Option A
Explanation:
Let the ages of Kunal and Sagar 6 years ago be 6x and 5x years respectively.
Then, (6x + 6) + 4 = 11 (5x + 6) + 4 10 10(6x + 10) = 11(5x + 10)
5x = 10
x = 2.
Sagar’s present age = (5x + 6) = 16 years.
3, 7, 6, 5, 9, 3, 12, 1, 15, (….)
Question:
3, 7, 6, 5, 9, 3, 12, 1, 15, (….)
[A].18 [B].
13 [C].
-1 [D].
3 Answer: Option C
Explanation:
There are two series, beginning respectively with 3 and 7. In one 3 is added and in another 2 is subtracted.
The next number is 1 – 2 = -1.